leetcode-101 对称二叉树 2015年03月01日 Tree 留言 101. 对称二叉树 难度: 简单 12345678910111213141516171819202122232425262728293031323334353637/** * Definition for a binary tree node. * type TreeNode struct { * Val int * Left *TreeNode * Right *TreeNode * } */func isSymmetric(root *TreeNode) bool { if root == nil { return true } return isSameNode(root.Left,root.Right) }func isSameNode(left *TreeNode,right *TreeNode) bool { if left == nil && right == nil { return true } if left == nil || right == nil { return false } if left.Val != right.Val { return false } return isSameNode(left.Left,right.Right) && isSameNode(left.Right,right.Left)} 文章目录 原文链接: https://dashen.tech/2015/03/01/leetcode-101-对称二叉树/ 版权声明: 转载请注明出处.